53=b/7+48

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Solution for 53=b/7+48 equation: 



53=b/7+48

We move all terms to the left:

53-(b/7+48)=0

We get rid of parentheses

-b/7-48+53=0

We multiply all the terms by the denominator


-b-48*7+53*7=0

We add all the numbers together, and all the variables

-1b+35=0

We move all terms containing b to the left, all other terms to the right

-b=-35

b=-35/-1

b=+35

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