32=-2(23-z)+3(z-4)

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Solution for 32=-2(23-z)+3(z-4) equation: 



32=-2(23-z)+3(z-4)

We move all terms to the left:

32-(-2(23-z)+3(z-4))=0

We add all the numbers together, and all the variables

-(-2(-1z+23)+3(z-4))+32=0



We calculate terms in parentheses: -(-2(-1z+23)+3(z-4)), so:

-2(-1z+23)+3(z-4)

We multiply parentheses

2z+3z-46-12

We add all the numbers together, and all the variables

5z-58

Back to the equation:

-(5z-58)



We get rid of parentheses

-5z+58+32=0

We add all the numbers together, and all the variables

-5z+90=0

We move all terms containing z to the left, all other terms to the right

-5z=-90

z=-90/-5

z=+18

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