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2x(-4x+2)=-5
We move all terms to the left:
2x(-4x+2)-(-5)=0
We add all the numbers together, and all the variables
2x(-4x+2)+5=0
We multiply parentheses
-8x^2+4x+5=0
a = -8; b = 4; c = +5;
Δ = b2-4ac
Δ = 42-4·(-8)·5
Δ = 176
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{176}=\sqrt{16*11}=\sqrt{16}*\sqrt{11}=4\sqrt{11}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4\sqrt{11}}{2*-8}=\frac{-4-4\sqrt{11}}{-16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4\sqrt{11}}{2*-8}=\frac{-4+4\sqrt{11}}{-16} $
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