(7y-22)+(3y+2)=180

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Solution for (7y-22)+(3y+2)=180 equation: 



(7y-22)+(3y+2)=180

We move all terms to the left:

(7y-22)+(3y+2)-(180)=0

We get rid of parentheses

7y+3y-22+2-180=0

We add all the numbers together, and all the variables

10y-200=0

We move all terms containing y to the left, all other terms to the right

10y=200

y=200/10

y=20

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