5(k+3)-(4k-4)=-8

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Solution for 5(k+3)-(4k-4)=-8 equation: 



5(k+3)-(4k-4)=-8

We move all terms to the left:

5(k+3)-(4k-4)-(-8)=0

We add all the numbers together, and all the variables

5(k+3)-(4k-4)+8=0

We multiply parentheses

5k-(4k-4)+15+8=0

We get rid of parentheses

5k-4k+4+15+8=0

We add all the numbers together, and all the variables

k+27=0

We move all terms containing k to the left, all other terms to the right

k=-27

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