30=-3(x-5)+10+2x

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Solution for 30=-3(x-5)+10+2x equation: 



30=-3(x-5)+10+2x

We move all terms to the left:

30-(-3(x-5)+10+2x)=0



We calculate terms in parentheses: -(-3(x-5)+10+2x), so:

-3(x-5)+10+2x

determiningTheFunctionDomain
-3(x-5)+2x+10

We add all the numbers together, and all the variables

2x-3(x-5)+10

We multiply parentheses

2x-3x+15+10

We add all the numbers together, and all the variables

-1x+25

Back to the equation:

-(-1x+25)



We get rid of parentheses

1x-25+30=0

We add all the numbers together, and all the variables

x+5=0

We move all terms containing x to the left, all other terms to the right

x=-5

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