(2/3)x-5=x+2

Solution for (2/3)x-5=x+2 equation:

(2/3)x-5=x+2

We move all terms to the left:

(2/3)x-5-(x+2)=0


Domain of the equation: 3)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+2/3)x-(x+2)-5=0

We multiply parentheses

2x^2-(x+2)-5=0

We get rid of parentheses

2x^2-x-2-5=0

We add all the numbers together, and all the variables

2x^2-1x-7=0

a = 2; b = -1; c = -7;
Δ = b2-4ac
Δ = -12-4·2·(-7)
Δ = 57
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{57}}{2*2}=\frac{1-\sqrt{57}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{57}}{2*2}=\frac{1+\sqrt{57}}{4}
$