-3=3/2(-1)+b

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Solution for -3=3/2(-1)+b equation: 



-3=3/2(-1)+b

We move all terms to the left:

-3-(3/2(-1)+b)=0



Domain of the equation: 2(-1)+b)!=0

b∈R



We multiply all the terms by the denominator


-(3-3*2(-1)+b)=0



We calculate terms in parentheses: -(3-3*2(-1)+b), so:

3-3*2(-1)+b

determiningTheFunctionDomain
b+3-3*2(-1)

We add all the numbers together, and all the variables

b+9

Back to the equation:

-(b+9)



We get rid of parentheses

-b-9=0

We add all the numbers together, and all the variables

-1b-9=0

We move all terms containing b to the left, all other terms to the right

-b=9

b=9/-1

b=-9

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