(b+7)/2=(7b+3)/3

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Solution for (b+7)/2=(7b+3)/3 equation: 



(b+7)/2=(7b+3)/3

We move all terms to the left:

(b+7)/2-((7b+3)/3)=0

We calculate fractions


b/()+(-((7b+3)*2)/()=0



We calculate terms in parentheses: +(-((7b+3)*2)/(), so:

-((7b+3)*2)/(

We multiply all the terms by the denominator


-((7b+3)*2)



We calculate terms in parentheses: -((7b+3)*2), so:

(7b+3)*2

We multiply parentheses

14b+6

Back to the equation:

-(14b+6)



We get rid of parentheses

-14b-6

Back to the equation:

+(-14b-6)



We get rid of parentheses

b/()-14b-6=0

We multiply all the terms by the denominator


b-14b*()-6*()=0

We add all the numbers together, and all the variables

b-14b*()=0

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