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3/8x+5=3x
We move all terms to the left:
3/8x+5-(3x)=0
Domain of the equation: 8x!=0We add all the numbers together, and all the variables
x!=0/8
x!=0
x∈R
-3x+3/8x+5=0
We multiply all the terms by the denominator
-3x*8x+5*8x+3=0
Wy multiply elements
-24x^2+40x+3=0
a = -24; b = 40; c = +3;
Δ = b2-4ac
Δ = 402-4·(-24)·3
Δ = 1888
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1888}=\sqrt{16*118}=\sqrt{16}*\sqrt{118}=4\sqrt{118}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(40)-4\sqrt{118}}{2*-24}=\frac{-40-4\sqrt{118}}{-48} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(40)+4\sqrt{118}}{2*-24}=\frac{-40+4\sqrt{118}}{-48} $
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