10x+(12-x)+54=10(12-x)+x

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Solution for 10x+(12-x)+54=10(12-x)+x equation:



10x+(12-x)+54=10(12-x)+x
We move all terms to the left:
10x+(12-x)+54-(10(12-x)+x)=0
We add all the numbers together, and all the variables
10x+(-1x+12)-(10(-1x+12)+x)+54=0
We get rid of parentheses
10x-1x-(10(-1x+12)+x)+12+54=0
We calculate terms in parentheses: -(10(-1x+12)+x), so:
10(-1x+12)+x
We add all the numbers together, and all the variables
x+10(-1x+12)
We multiply parentheses
x-10x+120
We add all the numbers together, and all the variables
-9x+120
Back to the equation:
-(-9x+120)
We add all the numbers together, and all the variables
9x-(-9x+120)+66=0
We get rid of parentheses
9x+9x-120+66=0
We add all the numbers together, and all the variables
18x-54=0
We move all terms containing x to the left, all other terms to the right
18x=54
x=54/18
x=3

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