3y-5y-1(2y-6)=8y-2(9y-6)

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Solution for 3y-5y-1(2y-6)=8y-2(9y-6) equation: 



3y-5y-1(2y-6)=8y-2(9y-6)

We move all terms to the left:

3y-5y-1(2y-6)-(8y-2(9y-6))=0

We add all the numbers together, and all the variables

-2y-1(2y-6)-(8y-2(9y-6))=0



We calculate terms in parentheses: -(8y-2(9y-6)), so:

8y-2(9y-6)

We multiply parentheses

8y-18y+12

We add all the numbers together, and all the variables

-10y+12

Back to the equation:

-(-10y+12)



We get rid of parentheses

-2y-1(2y-6)+10y-12=0

We add all the numbers together, and all the variables

8y-1(2y-6)-12=0

We move all terms containing y to the left, all other terms to the right

8y-1(2y-6)=12

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