1/2(4a-4)=1/3(12a-6)

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Solution for 1/2(4a-4)=1/3(12a-6) equation: 



1/2(4a-4)=1/3(12a-6)

We move all terms to the left:

1/2(4a-4)-(1/3(12a-6))=0



Domain of the equation: 2(4a-4)!=0

a∈R





Domain of the equation: 3(12a-6))!=0

a∈R



We calculate fractions


(3a1/(2(4a-4)*3(12a-6)))+(-2a4/(2(4a-4)*3(12a-6)))=0



We calculate terms in parentheses: +(3a1/(2(4a-4)*3(12a-6))), so:

3a1/(2(4a-4)*3(12a-6))

We multiply all the terms by the denominator


3a1

We add all the numbers together, and all the variables

3a

Back to the equation:

+(3a)





We calculate terms in parentheses: +(-2a4/(2(4a-4)*3(12a-6))), so:

-2a4/(2(4a-4)*3(12a-6))

We multiply all the terms by the denominator


-2a4

We add all the numbers together, and all the variables

-2a^4

We do not support eapression: a^4

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