3/5x=2/(x-7)

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Solution for 3/5x=2/(x-7) equation: 



3/5x=2/(x-7)

We move all terms to the left:

3/5x-(2/(x-7))=0



Domain of the equation: 5x!=0

x!=0/5

x!=0

x∈R





Domain of the equation: (x-7))!=0

x∈R



We calculate fractions


3x/(-30x^2)+(-(2*5x)/(-30x^2)=0



We calculate terms in parentheses: +(-(2*5x)/(-30x^2), so:

-(2*5x)/(-30x^2

We add all the numbers together, and all the variables

-(+2*5x)/(-30x^2

We multiply all the terms by the denominator


-(+2*5x)

We get rid of parentheses

-2*5x

Wy multiply elements

-10x

Back to the equation:

+(-10x)



We get rid of parentheses

3x/(-30x^2)-10x=0

We multiply all the terms by the denominator


-10x*(-30x^2)+3x=0

We multiply parentheses

300x^3+3x=0

We do not support expression: x^3

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