(3*2x)(3.25*2x)=15

Solution for (3*2x)(3.25*2x)=15 equation:

(3*2x)(3.25*2x)=15

We move all terms to the left:

(3*2x)(3.25*2x)-(15)=0

We add all the numbers together, and all the variables

(+3*2x)(+3.25*2x)-15=0

We multiply parentheses ..

(+39x^2)-15=0

We get rid of parentheses

39x^2-15=0

a = 39; b = 0; c = -15;
Δ = b2-4ac
Δ = 02-4·39·(-15)
Δ = 2340
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2340}=\sqrt{36*65}=\sqrt{36}*\sqrt{65}=6\sqrt{65}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{65}}{2*39}=\frac{0-6\sqrt{65}}{78}
=-\frac{6\sqrt{65}}{78}
=-\frac{\sqrt{65}}{13}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{65}}{2*39}=\frac{0+6\sqrt{65}}{78}
=\frac{6\sqrt{65}}{78}
=\frac{\sqrt{65}}{13}
$