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6x/4=(4/7)x+4
We move all terms to the left:
6x/4-((4/7)x+4)=0
Domain of the equation: 7)x+4)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
6x/4-((+4/7)x+4)=0
We calculate fractions
42x^2/28x+()/28x=0
We multiply all the terms by the denominator
42x^2+()=0
We add all the numbers together, and all the variables
42x^2=0
a = 42; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·42·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{84}=0$
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