3/4y+12=13

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Solution for 3/4y+12=13 equation: 



3/4y+12=13

We move all terms to the left:

3/4y+12-(13)=0



Domain of the equation: 4y!=0

y!=0/4

y!=0

y∈R



We add all the numbers together, and all the variables

3/4y-1=0

We multiply all the terms by the denominator


-1*4y+3=0

Wy multiply elements

-4y+3=0

We move all terms containing y to the left, all other terms to the right

-4y=-3

y=-3/-4

y=3/4

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