2(3z-1+4z+z+3)=58

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Solution for 2(3z-1+4z+z+3)=58 equation: 



2(3z-1+4z+z+3)=58

We move all terms to the left:

2(3z-1+4z+z+3)-(58)=0

We add all the numbers together, and all the variables

2(8z+2)-58=0

We multiply parentheses

16z+4-58=0

We add all the numbers together, and all the variables

16z-54=0

We move all terms containing z to the left, all other terms to the right

16z=54

z=54/16

z=3+3/8

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