2(3z-1+4z+3)=130

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Solution for 2(3z-1+4z+3)=130 equation: 



2(3z-1+4z+3)=130

We move all terms to the left:

2(3z-1+4z+3)-(130)=0

We add all the numbers together, and all the variables

2(7z+2)-130=0

We multiply parentheses

14z+4-130=0

We add all the numbers together, and all the variables

14z-126=0

We move all terms containing z to the left, all other terms to the right

14z=126

z=126/14

z=9

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