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3/4x+150=2x
We move all terms to the left:
3/4x+150-(2x)=0
Domain of the equation: 4x!=0We add all the numbers together, and all the variables
x!=0/4
x!=0
x∈R
-2x+3/4x+150=0
We multiply all the terms by the denominator
-2x*4x+150*4x+3=0
Wy multiply elements
-8x^2+600x+3=0
a = -8; b = 600; c = +3;
Δ = b2-4ac
Δ = 6002-4·(-8)·3
Δ = 360096
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{360096}=\sqrt{1936*186}=\sqrt{1936}*\sqrt{186}=44\sqrt{186}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(600)-44\sqrt{186}}{2*-8}=\frac{-600-44\sqrt{186}}{-16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(600)+44\sqrt{186}}{2*-8}=\frac{-600+44\sqrt{186}}{-16} $
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