(v-7)(v=2)

Solution for (v-7)(v=2) equation:

(v-7)(v=2)

We move all terms to the left:

(v-7)(v-(2))=0

We multiply parentheses ..

(+v^2-2v-7v+14)=0

We get rid of parentheses

v^2-2v-7v+14=0

We add all the numbers together, and all the variables

v^2-9v+14=0

a = 1; b = -9; c = +14;
Δ = b2-4ac
Δ = -92-4·1·14
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-5}{2*1}=\frac{4}{2}
=2
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+5}{2*1}=\frac{14}{2}
=7
$