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z+12/8=3
We move all terms to the left:
z+12/8-(3)=0
determiningTheFunctionDomain z-3+12/8=0
We multiply all the terms by the denominator
z*8+12-3*8=0
We add all the numbers together, and all the variables
z*8-12=0
Wy multiply elements
8z-12=0
We move all terms containing z to the left, all other terms to the right
8z=12
z=12/8
z=1+1/2
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