(4x+4)+(x-1)=33

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Solution for (4x+4)+(x-1)=33 equation: 



(4x+4)+(x-1)=33

We move all terms to the left:

(4x+4)+(x-1)-(33)=0

We get rid of parentheses

4x+x+4-1-33=0

We add all the numbers together, and all the variables

5x-30=0

We move all terms containing x to the left, all other terms to the right

5x=30

x=30/5

x=6

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