3/4(2x-3)=3/4(x+3)

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Solution for 3/4(2x-3)=3/4(x+3) equation: 



3/4(2x-3)=3/4(x+3)

We move all terms to the left:

3/4(2x-3)-(3/4(x+3))=0



Domain of the equation: 4(2x-3)!=0

x∈R





Domain of the equation: 4(x+3))!=0

x∈R



We calculate fractions


(12xx/(4(2x-3)*4(x+3)))+(-12x2/(4(2x-3)*4(x+3)))=0



We calculate terms in parentheses: +(12xx/(4(2x-3)*4(x+3))), so:

12xx/(4(2x-3)*4(x+3))

We multiply all the terms by the denominator


12xx

Back to the equation:

+(12xx)





We calculate terms in parentheses: +(-12x2/(4(2x-3)*4(x+3))), so:

-12x2/(4(2x-3)*4(x+3))

We multiply all the terms by the denominator


-12x2

We add all the numbers together, and all the variables

-12x^2

Back to the equation:

+(-12x^2)



We get rid of parentheses

-12x^2+12xx=0

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