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2(x-4)=3(2+x)
We move all terms to the left:
2(x-4)-(3(2+x))=0
We add all the numbers together, and all the variables
2(x-4)-(3(x+2))=0
We multiply parentheses
2x-(3(x+2))-8=0
We calculate terms in parentheses: -(3(x+2)), so:We get rid of parentheses
3(x+2)
We multiply parentheses
3x+6
Back to the equation:
-(3x+6)
2x-3x-6-8=0
We add all the numbers together, and all the variables
-1x-14=0
We move all terms containing x to the left, all other terms to the right
-x=14
x=14/-1
x=-14
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