6x(2x-5)+21=(4x-1)(3x+7)

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Solution for 6x(2x-5)+21=(4x-1)(3x+7) equation: 



6x(2x-5)+21=(4x-1)(3x+7)

We move all terms to the left:

6x(2x-5)+21-((4x-1)(3x+7))=0

We multiply parentheses

12x^2-30x-((4x-1)(3x+7))+21=0

We multiply parentheses ..

12x^2-((+12x^2+28x-3x-7))-30x+21=0



We calculate terms in parentheses: -((+12x^2+28x-3x-7)), so:

(+12x^2+28x-3x-7)

We get rid of parentheses

12x^2+28x-3x-7

We add all the numbers together, and all the variables

12x^2+25x-7

Back to the equation:

-(12x^2+25x-7)



We add all the numbers together, and all the variables

12x^2-30x-(12x^2+25x-7)+21=0

We get rid of parentheses

12x^2-12x^2-30x-25x+7+21=0

We add all the numbers together, and all the variables

-55x+28=0

We move all terms containing x to the left, all other terms to the right

-55x=-28

x=-28/-55

x=28/55

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