3+(b+1)=4b-1

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Solution for 3+(b+1)=4b-1 equation: 



3+(b+1)=4b-1

We move all terms to the left:

3+(b+1)-(4b-1)=0

We get rid of parentheses

b-4b+1+1+3=0

We add all the numbers together, and all the variables

-3b+5=0

We move all terms containing b to the left, all other terms to the right

-3b=-5

b=-5/-3

b=1+2/3

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