-3(v+1)=5v-5+5(2v+2)

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Solution for -3(v+1)=5v-5+5(2v+2) equation: 



-3(v+1)=5v-5+5(2v+2)

We move all terms to the left:

-3(v+1)-(5v-5+5(2v+2))=0

We multiply parentheses

-3v-(5v-5+5(2v+2))-3=0



We calculate terms in parentheses: -(5v-5+5(2v+2)), so:

5v-5+5(2v+2)

determiningTheFunctionDomain
5v+5(2v+2)-5

We multiply parentheses

5v+10v+10-5

We add all the numbers together, and all the variables

15v+5

Back to the equation:

-(15v+5)



We get rid of parentheses

-3v-15v-5-3=0

We add all the numbers together, and all the variables

-18v-8=0

We move all terms containing v to the left, all other terms to the right

-18v=8

v=8/-18

v=-4/9

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