3(z+7)=3(z-2)

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Solution for 3(z+7)=3(z-2) equation: 



3(z+7)=3(z-2)

We move all terms to the left:

3(z+7)-(3(z-2))=0

We multiply parentheses

3z-(3(z-2))+21=0



We calculate terms in parentheses: -(3(z-2)), so:

3(z-2)

We multiply parentheses

3z-6

Back to the equation:

-(3z-6)



We get rid of parentheses

3z-3z+6+21=0

We add all the numbers together, and all the variables

27!=0

There is no solution for this equation

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