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2(x/4)+12=-2(x/3)
We move all terms to the left:
2(x/4)+12-(-2(x/3))=0
We add all the numbers together, and all the variables
2(+x/4)-(-2(+x/3))+12=0
We multiply parentheses
2x-(-2(+x/3))+12=0
We multiply all the terms by the denominator
2x*3))-(-2(+x+12*3))=0
We add all the numbers together, and all the variables
2x*3))-(-2(x+36))=0
We add all the numbers together, and all the variables
2x*3))-(-2(x=0
Wy multiply elements
6x^2=0
a = 6; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·6·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{12}=0$
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