3(r+48)=7(r-10)

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Solution for 3(r+48)=7(r-10) equation: 



3(r+48)=7(r-10)

We move all terms to the left:

3(r+48)-(7(r-10))=0

We multiply parentheses

3r-(7(r-10))+144=0



We calculate terms in parentheses: -(7(r-10)), so:

7(r-10)

We multiply parentheses

7r-70

Back to the equation:

-(7r-70)



We get rid of parentheses

3r-7r+70+144=0

We add all the numbers together, and all the variables

-4r+214=0

We move all terms containing r to the left, all other terms to the right

-4r=-214

r=-214/-4

r=53+1/2

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