3(y-2)+1=2(y-3)-(y+1)

Solution for 3(y-2)+1=2(y-3)-(y+1) equation:

3(y-2)+1=2(y-3)-(y+1)

We move all terms to the left:

3(y-2)+1-(2(y-3)-(y+1))=0

We multiply parentheses

3y-(2(y-3)-(y+1))-6+1=0


We calculate terms in parentheses: -(2(y-3)-(y+1)), so:

2(y-3)-(y+1)

We multiply parentheses

2y-(y+1)-6

We get rid of parentheses

2y-y-1-6

We add all the numbers together, and all the variables

y-7

Back to the equation:

-(y-7)


We add all the numbers together, and all the variables

3y-(y-7)-5=0

We get rid of parentheses

3y-y+7-5=0

We add all the numbers together, and all the variables

2y+2=0

We move all terms containing y to the left, all other terms to the right

2y=-2

y=-2/2

y=-1