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3(2-5)=9(10-x)
We move all terms to the left:
3(2-5)-(9(10-x))=0
We add all the numbers together, and all the variables
-(9(-1x+10))+3(-3)=0
We add all the numbers together, and all the variables
-(9(-1x+10))-9=0
We calculate terms in parentheses: -(9(-1x+10)), so:We get rid of parentheses
9(-1x+10)
We multiply parentheses
-9x+90
Back to the equation:
-(-9x+90)
9x-90-9=0
We add all the numbers together, and all the variables
9x-99=0
We move all terms containing x to the left, all other terms to the right
9x=99
x=99/9
x=11
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