(b-5)+(2b+50)+4b=360

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Solution for (b-5)+(2b+50)+4b=360 equation: 



(b-5)+(2b+50)+4b=360

We move all terms to the left:

(b-5)+(2b+50)+4b-(360)=0

We add all the numbers together, and all the variables

4b+(b-5)+(2b+50)-360=0

We get rid of parentheses

4b+b+2b-5+50-360=0

We add all the numbers together, and all the variables

7b-315=0

We move all terms containing b to the left, all other terms to the right

7b=315

b=315/7

b=45

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