(2/x-2)+(4/x+1)=3

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Solution for (2/x-2)+(4/x+1)=3 equation: 



(2/x-2)+(4/x+1)=3

We move all terms to the left:

(2/x-2)+(4/x+1)-(3)=0



Domain of the equation: x-2)!=0

x∈R





Domain of the equation: x+1)!=0

x∈R



We get rid of parentheses

2/x+4/x-2+1-3=0

We multiply all the terms by the denominator


-2*x+1*x-3*x+2+4=0

We add all the numbers together, and all the variables

-4x+6=0

We move all terms containing x to the left, all other terms to the right

-4x=-6

x=-6/-4

x=1+1/2

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