3(y+7)=2(y+1)+20

Solution for 3(y+7)=2(y+1)+20 equation:

3(y+7)=2(y+1)+20

We move all terms to the left:

3(y+7)-(2(y+1)+20)=0

We multiply parentheses

3y-(2(y+1)+20)+21=0


We calculate terms in parentheses: -(2(y+1)+20), so:

2(y+1)+20

We multiply parentheses

2y+2+20

We add all the numbers together, and all the variables

2y+22

Back to the equation:

-(2y+22)


We get rid of parentheses

3y-2y-22+21=0

We add all the numbers together, and all the variables

y-1=0

We move all terms containing y to the left, all other terms to the right

y=1