5(y+1)=3(y-2)+12

Solution for 5(y+1)=3(y-2)+12 equation:

5(y+1)=3(y-2)+12

We move all terms to the left:

5(y+1)-(3(y-2)+12)=0

We multiply parentheses

5y-(3(y-2)+12)+5=0


We calculate terms in parentheses: -(3(y-2)+12), so:

3(y-2)+12

We multiply parentheses

3y-6+12

We add all the numbers together, and all the variables

3y+6

Back to the equation:

-(3y+6)


We get rid of parentheses

5y-3y-6+5=0

We add all the numbers together, and all the variables

2y-1=0

We move all terms containing y to the left, all other terms to the right

2y=1

y=1/2

y=1/2