3(2t+1)=4(5-t)

Solution for 3(2t+1)=4(5-t) equation:

3(2t+1)=4(5-t)

We move all terms to the left:

3(2t+1)-(4(5-t))=0

We add all the numbers together, and all the variables

3(2t+1)-(4(-1t+5))=0

We multiply parentheses

6t-(4(-1t+5))+3=0


We calculate terms in parentheses: -(4(-1t+5)), so:

4(-1t+5)

We multiply parentheses

-4t+20

Back to the equation:

-(-4t+20)


We get rid of parentheses

6t+4t-20+3=0

We add all the numbers together, and all the variables

10t-17=0

We move all terms containing t to the left, all other terms to the right

10t=17

t=17/10

t=1+7/10