3(2t+1)=4(5-2)

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Solution for 3(2t+1)=4(5-2) equation: 



3(2t+1)=4(5-2)

We move all terms to the left:

3(2t+1)-(4(5-2))=0

We add all the numbers together, and all the variables

3(2t+1)-(43)=0

We add all the numbers together, and all the variables

3(2t+1)-43=0

We multiply parentheses

6t+3-43=0

We add all the numbers together, and all the variables

6t-40=0

We move all terms containing t to the left, all other terms to the right

6t=40

t=40/6

t=6+2/3

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