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3(x-5)=2(x-10)
We move all terms to the left:
3(x-5)-(2(x-10))=0
We multiply parentheses
3x-(2(x-10))-15=0
We calculate terms in parentheses: -(2(x-10)), so:We get rid of parentheses
2(x-10)
We multiply parentheses
2x-20
Back to the equation:
-(2x-20)
3x-2x+20-15=0
We add all the numbers together, and all the variables
x+5=0
We move all terms containing x to the left, all other terms to the right
x=-5
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