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5x+2-2x=3(x+1)-1
We move all terms to the left:
5x+2-2x-(3(x+1)-1)=0
We add all the numbers together, and all the variables
3x-(3(x+1)-1)+2=0
We calculate terms in parentheses: -(3(x+1)-1), so:We get rid of parentheses
3(x+1)-1
We multiply parentheses
3x+3-1
We add all the numbers together, and all the variables
3x+2
Back to the equation:
-(3x+2)
3x-3x-2+2=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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