16-2(3x+5)=3x+42

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Solution for 16-2(3x+5)=3x+42 equation: 



16-2(3x+5)=3x+42

We move all terms to the left:

16-2(3x+5)-(3x+42)=0

We multiply parentheses

-6x-(3x+42)-10+16=0

We get rid of parentheses

-6x-3x-42-10+16=0

We add all the numbers together, and all the variables

-9x-36=0

We move all terms containing x to the left, all other terms to the right

-9x=36

x=36/-9

x=-4

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