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1/6x-0.83=1/2x+3
We move all terms to the left:
1/6x-0.83-(1/2x+3)=0
Domain of the equation: 6x!=0
x!=0/6
x!=0
x∈R
Domain of the equation: 2x+3)!=0We get rid of parentheses
x∈R
1/6x-1/2x-3-0.83=0
We calculate fractions
2x/12x^2+(-6x)/12x^2-3-0.83=0
We add all the numbers together, and all the variables
2x/12x^2+(-6x)/12x^2-3.83=0
We multiply all the terms by the denominator
2x+(-6x)-(3.83)*12x^2=0
We get rid of parentheses
2x-6x-(3.83)*12x^2=0
We add all the numbers together, and all the variables
-4x-(3.83)*12x^2=0
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