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3(x-5)-5(x-3)=x+2(x-6)
We move all terms to the left:
3(x-5)-5(x-3)-(x+2(x-6))=0
We multiply parentheses
3x-5x-(x+2(x-6))-15+15=0
We calculate terms in parentheses: -(x+2(x-6)), so:We add all the numbers together, and all the variables
x+2(x-6)
We multiply parentheses
x+2x-12
We add all the numbers together, and all the variables
3x-12
Back to the equation:
-(3x-12)
-2x-(3x-12)=0
We get rid of parentheses
-2x-3x+12=0
We add all the numbers together, and all the variables
-5x+12=0
We move all terms containing x to the left, all other terms to the right
-5x=-12
x=-12/-5
x=2+2/5
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