3(x-5)+6x=4(2x+3)

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Solution for 3(x-5)+6x=4(2x+3) equation: 



3(x-5)+6x=4(2x+3)

We move all terms to the left:

3(x-5)+6x-(4(2x+3))=0

We add all the numbers together, and all the variables

6x+3(x-5)-(4(2x+3))=0

We multiply parentheses

6x+3x-(4(2x+3))-15=0



We calculate terms in parentheses: -(4(2x+3)), so:

4(2x+3)

We multiply parentheses

8x+12

Back to the equation:

-(8x+12)



We add all the numbers together, and all the variables

9x-(8x+12)-15=0

We get rid of parentheses

9x-8x-12-15=0

We add all the numbers together, and all the variables

x-27=0

We move all terms containing x to the left, all other terms to the right

x=27

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