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5(x-2)+5x=3(3x+5)
We move all terms to the left:
5(x-2)+5x-(3(3x+5))=0
We add all the numbers together, and all the variables
5x+5(x-2)-(3(3x+5))=0
We multiply parentheses
5x+5x-(3(3x+5))-10=0
We calculate terms in parentheses: -(3(3x+5)), so:We add all the numbers together, and all the variables
3(3x+5)
We multiply parentheses
9x+15
Back to the equation:
-(9x+15)
10x-(9x+15)-10=0
We get rid of parentheses
10x-9x-15-10=0
We add all the numbers together, and all the variables
x-25=0
We move all terms containing x to the left, all other terms to the right
x=25
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