3+4(s+3)=4(2s+4)-8s

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Solution for 3+4(s+3)=4(2s+4)-8s equation: 



3+4(s+3)=4(2s+4)-8s

We move all terms to the left:

3+4(s+3)-(4(2s+4)-8s)=0

We multiply parentheses

4s-(4(2s+4)-8s)+12+3=0



We calculate terms in parentheses: -(4(2s+4)-8s), so:

4(2s+4)-8s

We add all the numbers together, and all the variables

-8s+4(2s+4)

We multiply parentheses

-8s+8s+16

We add all the numbers together, and all the variables

16

Back to the equation:

-(16)



We add all the numbers together, and all the variables

4s-1=0

We move all terms containing s to the left, all other terms to the right

4s=1

s=1/4

s=1/4

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