15=(2x+3x+10)/2

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Solution for 15=(2x+3x+10)/2 equation: 



15=(2x+3x+10)/2

We move all terms to the left:

15-((2x+3x+10)/2)=0

We add all the numbers together, and all the variables

-((5x+10)/2)+15=0

We multiply all the terms by the denominator


-((5x+10)+15*2)=0



We calculate terms in parentheses: -((5x+10)+15*2), so:

(5x+10)+15*2

We add all the numbers together, and all the variables

(5x+10)+30

We get rid of parentheses

5x+10+30

We add all the numbers together, and all the variables

5x+40

Back to the equation:

-(5x+40)



We get rid of parentheses

-5x-40=0

We move all terms containing x to the left, all other terms to the right

-5x=40

x=40/-5

x=-8

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