(1)/(2)(10+12n)=(1)/(3)(15n+5)

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Solution for (1)/(2)(10+12n)=(1)/(3)(15n+5) equation: 



(1)/(2)(10+12n)=(1)/(3)(15n+5)

We move all terms to the left:

(1)/(2)(10+12n)-((1)/(3)(15n+5))=0



Domain of the equation: 2(10+12n)!=0

n∈R





Domain of the equation: 3(15n+5))!=0

n∈R



We add all the numbers together, and all the variables

1/2(12n+10)-(1/3(15n+5))=0

We calculate fractions


(3n1/(2(12n+10)*3(15n+5)))+(-2n1/(2(12n+10)*3(15n+5)))=0



We calculate terms in parentheses: +(3n1/(2(12n+10)*3(15n+5))), so:

3n1/(2(12n+10)*3(15n+5))

We multiply all the terms by the denominator


3n1

We add all the numbers together, and all the variables

3n

Back to the equation:

+(3n)





We calculate terms in parentheses: +(-2n1/(2(12n+10)*3(15n+5))), so:

-2n1/(2(12n+10)*3(15n+5))

We multiply all the terms by the denominator


-2n1

We add all the numbers together, and all the variables

-2n

Back to the equation:

+(-2n)



We get rid of parentheses

3n-2n=0

We add all the numbers together, and all the variables

n=0

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