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3(x-2)=5-(x-1)
We move all terms to the left:
3(x-2)-(5-(x-1))=0
We multiply parentheses
3x-(5-(x-1))-6=0
We calculate terms in parentheses: -(5-(x-1)), so:We get rid of parentheses
5-(x-1)
determiningTheFunctionDomain -(x-1)+5
We get rid of parentheses
-x+1+5
We add all the numbers together, and all the variables
-1x+6
Back to the equation:
-(-1x+6)
3x+1x-6-6=0
We add all the numbers together, and all the variables
4x-12=0
We move all terms containing x to the left, all other terms to the right
4x=12
x=12/4
x=3
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